h^2-18h=-20

Solution for h^2-18h=-20 equation:

h^2-18h=-20

We move all terms to the left:

h^2-18h-(-20)=0

We add all the numbers together, and all the variables

h^2-18h+20=0

a = 1; b = -18; c = +20;
Δ = b2-4ac
Δ = -182-4·1·20
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{61}}{2*1}=\frac{18-2\sqrt{61}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{61}}{2*1}=\frac{18+2\sqrt{61}}{2}
$